Asked by Trish
What is the molality of a 30.0% by mass hydrochloric acid solution ? The density of the solution is 1.0980g/mol.
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Answered by
Doc P-48
molality = moles HCl/Kg Solvent
Given 30% Soln by mass = 30gHCl/100gSoln
Moles HCl = (30g/36g/mol) = 0.833mole
Kg Solvent = (100gSoln/1.098g/ml) = 91.1ml = 91.1gms Soln(1.10g/ml 30%HClsoln*)= 100.21gms of 30%HCLSoln = 0.1002Kg Soln = 60%(0.1002Kg) = 0.60(0.1002)Kg Solvent = 0.0601Kg Solvent
*specific gravity of 30%HCl aqueous soln = 1.10 = 1.10g/ml if solvent is HOH.
molality = (0.833moleHCl)/(0.0601KgSolvent)
=13.85 molal HCl soln
Given 30% Soln by mass = 30gHCl/100gSoln
Moles HCl = (30g/36g/mol) = 0.833mole
Kg Solvent = (100gSoln/1.098g/ml) = 91.1ml = 91.1gms Soln(1.10g/ml 30%HClsoln*)= 100.21gms of 30%HCLSoln = 0.1002Kg Soln = 60%(0.1002Kg) = 0.60(0.1002)Kg Solvent = 0.0601Kg Solvent
*specific gravity of 30%HCl aqueous soln = 1.10 = 1.10g/ml if solvent is HOH.
molality = (0.833moleHCl)/(0.0601KgSolvent)
=13.85 molal HCl soln
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