Asked by C
What is the (a) molality, (b) freezing point, and (c) boiling point of a solution containing 2.29 g napthalene (C10H8) in 44.6 g of benzene (C6H6)?
Answers
Answered by
DrBob222
mols C10H8 = grams/molar mass
m = mols/kg solvent.
delta T = Kf*m
Substitute and solve for dT, then subtract from zero to arrive at the new freezing point.
delta T = Kb*m
Subtitut and solve for delta T and add to 100 C to arrive at the new boiling point.
m = mols/kg solvent.
delta T = Kf*m
Substitute and solve for dT, then subtract from zero to arrive at the new freezing point.
delta T = Kb*m
Subtitut and solve for delta T and add to 100 C to arrive at the new boiling point.
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