Question
An Olympic long jumper is capable of jumping 8.44m. Assuming his horizontal speed is 5.644m/s as he leaves the ground, how high does he go?
Answers
bobpursley
time in air:
distance=vh*time
time= 8.44/5.644 sec
so max heigh give a falling time 1/2 time in air.
hf=hmax-1/2 *9.8*(1/2*8.44/5.644)^2
hf=0, solve for hmax
distance=vh*time
time= 8.44/5.644 sec
so max heigh give a falling time 1/2 time in air.
hf=hmax-1/2 *9.8*(1/2*8.44/5.644)^2
hf=0, solve for hmax