Asked by Rich
a long jumper jumps 10m and leaves the ground at an angle of 45 degrees.determine the speed he leaves the the ground at,
Answers
Answered by
bobpursley
The upward velocity is Vsin45. The horizontal veloicty is Vcos45
horizontal:
10m=Vcos45*t
time= 14.1/V
Vertical
Hfinal=hinitial+Vsin45*t- 4.9t^2
put what we found in for time, solve for v.
horizontal:
10m=Vcos45*t
time= 14.1/V
Vertical
Hfinal=hinitial+Vsin45*t- 4.9t^2
put what we found in for time, solve for v.
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