Asked by Anonymous
The wheels of a skateboard roll without slipping as it accelerates at 0.45 m/s2 down an 75-m-long hill.
If the skateboarder travels at 1.8 m/s at the top of the hill, what is the average angular speed of the 2.6-cm-radius whe els during the entire trip down the hill?
I first found out the velocity of the skater which was 38.4 m/s using v^2=vo^2+2aX and then plugged the velocity into v=vo+at to find time but the time came out to be 3.73 s which is too little? I'm not sure if what I did is right.. I was going to plug the time into w=wo+at to find the angular velocity.
If the skateboarder travels at 1.8 m/s at the top of the hill, what is the average angular speed of the 2.6-cm-radius whe els during the entire trip down the hill?
I first found out the velocity of the skater which was 38.4 m/s using v^2=vo^2+2aX and then plugged the velocity into v=vo+at to find time but the time came out to be 3.73 s which is too little? I'm not sure if what I did is right.. I was going to plug the time into w=wo+at to find the angular velocity.
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