A boy on a 2.2kg skateboard initially at rest tosses a 7.9kg jug of water in the forward direction.

If the jug has a speed of 3.2m/s relative to the ground and the boy and skateboard move in the opposite direction at .56m/s, find the boy's mass.
Answer in units of kg.

4 answers

initial momentum= final momentum
0=(M+2.2).56+7.9(-3.2)

solve for M
24.048 kg
You’re wrong
42.942

(If you have 2.3 kg skate 8.4kg jug.... = 42.5)
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