Asked by Morgan

Calculate the value of work, w, for the following system if 26.7 g of NaN3 reacts completely at 1.00 atm and 22 °C.

Answers

Answered by DrBob222
NaN3 ==> Na + 3/2 N2
Use PV = nRT. n = grams NaN3/molar mass NaN3. Convert that to mols N2 and plug that into PV = nRT; Solve for V. Then work = pdV and the sign will be negative since the system is doing work in the expansion.
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