Asked by Anthony
A rocket is launched at t=0 seconds. Its height, in feet, above sea-level, as a function of time,t, is given by
h(t)=-16t^2+112t+480
When does the rocket hit the ground after it is launched?
h(t)=-16t^2+112t+480
When does the rocket hit the ground after it is launched?
Answers
Answered by
Damon
0 = 16 t^2 - 112 t - 480
0 = t^2 -7 t - 30
0 = (t-10)(t+7)
t = 10
the other root was before it was launched
0 = t^2 -7 t - 30
0 = (t-10)(t+7)
t = 10
the other root was before it was launched
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