A) Plug in 50 for s in the equation.
50=-16t^2+100t
Move the 50 over.
0=-16t^2+100t+50
Use the quadratic formula to solve for t and neglect the negative answer. If you don't know the quadratic formula, it's:
(-b plus or minus the square root of b^2-4ac)/2a
B)Plug 0 in for s (since the ground represents 0 feet) and follow the same steps from A).
If a projectile is shot vertically upward from the ground with an initial velocity of 100 ft per sec, neglecting air resistance, its height s (in feet) above the ground t seconds after projection is given by s= -16t^2 + 100t
a) After how many seconds will it be 50ft above the ground ?
B) How long will it take for the projectile to return to ground ?
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