Asked by Christian
If a projectile is shot under an angle of 30* with a force of 500N what is the time the projectile reaches the maximum hight.The projectile's mass is 100g.(g=10N/kg)
Answers
Answered by
Steve
recall that the height h is
h(t) = (500 sin30°)t - 5t^2
Now just find the vertex of that parabola.
h(t) = (500 sin30°)t - 5t^2
Now just find the vertex of that parabola.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.