Asked by Christian

If a projectile is shot under an angle of 30* with a force of 500N what is the time the projectile reaches the maximum hight.The projectile's mass is 100g.(g=10N/kg)

Answers

Answered by Steve
recall that the height h is

h(t) = (500 sin30°)t - 5t^2

Now just find the vertex of that parabola.
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