Question

In physics, one learns that the height of an object thrown upward from an initial height of h0 feet with an initial velocity of v0 (in feet per second) is given by the formula
h(t)=−16t^2+v0t+h0 feet
where t is the amount of time in seconds after the ball was thrown. Also, the velocity of the object is given by
v(t)=−32t+v0. feet per second

When one uses the metric system, the equations become
h(t)=−4.9t^2+v0t+h0 meters
and
v(t)=−9.8t+v0 meters per second.



An object is projected upward from a height of 33 feet at a velocity of 97 feet per second.


Find the velocity of the object when it hits the ground.

Answer 1

see other post.