Asked by steve Alexander
i just want to know form where i got on this formula the 4.9t² on this formula s=4.9t²+Vot+h because the book only say that a physics theory shows that when an object is thrown upward with an initial velocity Vo, its approximate height is given by that quadratic function
i will appreciate if you can explain me that because i have a math problem that uses that equation but i don't know from wheres that 4.9t²
i will appreciate if you can explain me that because i have a math problem that uses that equation but i don't know from wheres that 4.9t²
Answers
Answered by
bobpursley
It comes from calculus, and I assume you do not know that.
Newton found the velocity of a falling object was proportional to the time it fell.
vincreased= constant*time
but the constant we now call g, 9.8m/s^2, which comes from his universal gravitational equation.
From this, we get
Vfinal=vinitial+ g*time
Now the distance something falls is the average velocity, times time.
distance=(vfinal+vinitial)/2 * time
d=(1/2 (vinital+ g*time + vinitial)*time
= 1/2 (2vinitial*time + g*time^2)
= vinitial*time + 1/2 g*time^2
of course, 1/2 g = 4.9 m/s^2
Newton found the velocity of a falling object was proportional to the time it fell.
vincreased= constant*time
but the constant we now call g, 9.8m/s^2, which comes from his universal gravitational equation.
From this, we get
Vfinal=vinitial+ g*time
Now the distance something falls is the average velocity, times time.
distance=(vfinal+vinitial)/2 * time
d=(1/2 (vinital+ g*time + vinitial)*time
= 1/2 (2vinitial*time + g*time^2)
= vinitial*time + 1/2 g*time^2
of course, 1/2 g = 4.9 m/s^2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.