Asked by Ray

Using your mass of Mg (0.101g), and assuming all of the Mg burns in oxygen and forms the theoretical predicted product, calculate the theoretical yield of magnesium oxide.

I wrote out the equation and it turned out to be:

2Mg+O2->2MgO

I have my mass of Mg but how do I get to the theoretical yield of how much MgO is formed? Thanks in advance!
Answered by Ray
I tried doing some conversion factors and came up with this:

(0.101g Mg)(1mol MgO) |(40.31g MgO)
----------------------
(24.31g Mg)|(1mol MgO)

=~0.167g MgO as my theoretical yield if I had a mass of 0.101g of Mg
Did I do this correctly?
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