Asked by Komal
Laws passed in some states define a drunk driver as one who drives with a blood alcohol level of 0.08% by mass or higher. the level of alocohol can be determinded byt titrating blood plasma with pottasium dichromate according to the unbalanced redox reaction.
igot the balanced equation--
C2O72- + 14 H + 3H2O + C2H5OH ---> 2cr3+ + 7H2O + 2CO2 + 6H
-- assuming that the only substance that reacts with the dichromate in blood plasma is alcohol, is a person legally drunk if 38.94 ML of 0.0723M potassium dichromate is required to titrate 50.0 g sample of blood plasma?
HELP ME PLZ.. THIS IS FOR A GRADE.. THANKYOU! :)
igot the balanced equation--
C2O72- + 14 H + 3H2O + C2H5OH ---> 2cr3+ + 7H2O + 2CO2 + 6H
-- assuming that the only substance that reacts with the dichromate in blood plasma is alcohol, is a person legally drunk if 38.94 ML of 0.0723M potassium dichromate is required to titrate 50.0 g sample of blood plasma?
HELP ME PLZ.. THIS IS FOR A GRADE.. THANKYOU! :)
Answers
Answered by
DrBob222
Check your equation. I don't think it is balanced. I see 26 H atoms on the left and 20 on the right.
Step 1. moles dichromate = M x L
Step 2. Convert moles dichromate to moles alcohol using the coefficients in the balanced equation.(I think you need to start with 2Cr2O7^-2.
Step 3. Convert moles alcohol to grams alcohol.
Step 4. % ethanol = (g alcohol/50)*100=??
Step 1. moles dichromate = M x L
Step 2. Convert moles dichromate to moles alcohol using the coefficients in the balanced equation.(I think you need to start with 2Cr2O7^-2.
Step 3. Convert moles alcohol to grams alcohol.
Step 4. % ethanol = (g alcohol/50)*100=??
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