Asked by William

We need assistance solving

3 + 2(k+1) = 6 + 3k

I know the 2(k+1) has to become 2k + 2

then we have 3 + 2k + 2 = 6 + 3k
then we can subtract 3k from both sides to get
3 +2k + 2 - 3K = 6
But can I combine the 3+2 on the left
and the 2k - 3k to get -1k?

leaving us with 5 -1k = 6
-1k = 6-5
-1k = 1
k = -1
Answered by Ms. Sue
Great! You are correct!

Answered by William
Thank you! I had figured it out four ways the wrong way. Don't know what I'm doing wrong. Think it may have to do with the MiDAS rule or something but cannot figure it out.
Answered by Writeacher
PEMDAS is the order of operations!
(Please excuse my dear Aunt Sally = PEMDAS mnemonic = easier to remember)
Parentheses
Exponents
Multiply
Divide
Add
Subtract

http://www.mathgoodies.com/lessons/vol7/order_operations.html
Answered by William
5/6t + 4 = 2 - 1/6t

Is the best thing to do first in this case to get rid of the fractions? Should I turn them into decimals or multiply both sides by 6? And when I multiply by 6, do I multiply each factor by 6. SO it becomes

5t + 4(6) = 2(6) -t
?
Thanks.
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the key is to try its very clear. Just use your distributive property when its ilke 3(3*4) . Your just nervous because it looks like a big problem
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haha fantastic -_-
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