Asked by Dave
Use the quotient rule to find the derivative of cot x.
I tried to solve this, but somehow I got (sec^2x)/(tanx)^2.
I tried to solve this, but somehow I got (sec^2x)/(tanx)^2.
Answers
Answered by
Steve
this is (almost) correct, since
sec^2/tan^2 = 1/cos^2 * cos^2/sin^2 = csc^2
Actually, the derivative is -csc^2x
cotx = cosx/sinx
d/dx(cotx) = (-sinx*sinx - cosx*cosx)/sin^2x
= -(sin^2x-cos^2x)/sin^2x
= -1/sin^2x
= -csc^2x
Next time, show <u>your</u> work, so we can see what went wrong.
sec^2/tan^2 = 1/cos^2 * cos^2/sin^2 = csc^2
Actually, the derivative is -csc^2x
cotx = cosx/sinx
d/dx(cotx) = (-sinx*sinx - cosx*cosx)/sin^2x
= -(sin^2x-cos^2x)/sin^2x
= -1/sin^2x
= -csc^2x
Next time, show <u>your</u> work, so we can see what went wrong.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.