Question

A projectile is launched directly upward from the top of a 112 - foot building with an initial velocity (speed) of 96 feet per second. This translates to the h(t) = -16t^2 + 96t + 112 where h(t) is the height of the projectile in feet and t is the time in seconds after it is launched. When will the projectile hit the ground?

t = 7 seconds after it is launched

Is this correct?

Answer 1

16 t^2 - 96 t - 112 = 0
t^2 - 6 t - 7 = 0
(t-7)(t+1) = 0
t = 7
so yes

Answer 2

Thanks Damon!