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0.550 L of 0.420 M H2SO4 is mixed with 0.500 L of 0.270 M KOH. What concentration of sulfuric acid remains after neutralization...Asked by james
0.350 L of 0.470 M H2SO4 is mixed with 0.300 L of 0.250 M KOH. What concentration of sulfuric acid remains after neutralization?
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Answered by
DrBob222
Your question is poorly worded in my opinion. By my definitions, if the H2SO4 is neutralized then there will not be ANY H2SO4 left. What the problem means, I think, is after the addition of that much KOH to that much H2SO4, what is the concn of H2SO4.
H2SO4 + 2NaOH ==> Na2SO4 + 2H2O
mols H2SO4 = M x L = estimated 0.16
mols KOH added = M x L = estimated 0.075
So 0.075 mols KOH uses 1/2 x 0.075 mols H2SO4 or estimated 0.037. Then 0.16-0.o37 = approx 0.12 mols H2SO4 remaining.
(H2SO4) = mols/total L.
H2SO4 + 2NaOH ==> Na2SO4 + 2H2O
mols H2SO4 = M x L = estimated 0.16
mols KOH added = M x L = estimated 0.075
So 0.075 mols KOH uses 1/2 x 0.075 mols H2SO4 or estimated 0.037. Then 0.16-0.o37 = approx 0.12 mols H2SO4 remaining.
(H2SO4) = mols/total L.
Answered by
Anonymous
HUH
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