Asked by Audrey

A water trough is 5 m long and has a cross-section in the shape of an isosceles trapezoid that is 30 cm wide at the bottom, 70 cm wide at the top, and has height 40 cm. If the trough is being filled with water at the rate of 0.2 m3/min how fast is the water level rising when the water is 10 cm deep?
Round your answer to 3 decimal digits.

Answers

Answered by Steve
see related questions below.
Answered by Audrey
After seeing other examples on here, I tried to do it myself. I got .05 m/min but the online system I do my homework on, said it was wrong.
Answered by Steve
I plugged in your numbers to Damon's solution and got 40 cm/min

What work do you have to show?
Answered by Audrey
I tried that but that was wrong too.



Q= 0.2 m^3/min
A=surface area= length(width) at 10 cm deep depth is 1/2 the height. Width= 30 + 1/2(70-30)= 50 cm or .5 m



dh/dt= QA

A= 5(.5)= 2.5 m^3

dh/dt= (.2)(2.5)= .05 m/min

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