Question

A reaction in a calorimeter containing 80.0 g of water at 20 degrees Celsius causes the temperature to fall by 1.5 degrees. what is the thermal energy of the water? I got 6.2 J or 6192.32 kJ but they say 5.02 x 10^4 kJ idk what I am doing wrong

Answer 1

q=mc(delta-T) = 80g(4.184j/g-C)(1.5 C)= 502 joules x (1 Kj/1000 joules) = 0.00502 Kj = 5.02E-4Kj