Question
A conical tank with height is 10 and radius is 5 is being filled with water at 4m^3/s. Solve how fast is the water when = 3m
Answers
Damon
find radius of surface as a function of height h
r/h = 5/10 = .5
then surface area = pi r^2 = pi (.25 h^2)
change in volume dv = surface area * dh
dv = pi (.25 h^2) dh
and
dv/dt = .25 pi h^2 dh/dt
4 = .25 pi (9) dh/dt
solve for dh/dt
r/h = 5/10 = .5
then surface area = pi r^2 = pi (.25 h^2)
change in volume dv = surface area * dh
dv = pi (.25 h^2) dh
and
dv/dt = .25 pi h^2 dh/dt
4 = .25 pi (9) dh/dt
solve for dh/dt