Asked by Zaza
H3C6H5O7(aq) + 3NaHCO3(aq)----Na3C6H5O7(aq) + 3H2O(i) + 3CO2.
NaHCO3 = 2.00g
H3C6H5O7 = 0.76
CO2 = 0.07g
1.Determine which reactant is the limiting reactant . describe your reasoning.
2. Calculate the theoretical yield of carbon dioxide in the plastic
3. what is the actual yield in this experiment.
DrBobb222
NaHCO3 = 2.00g
H3C6H5O7 = 0.76
CO2 = 0.07g
1.Determine which reactant is the limiting reactant . describe your reasoning.
2. Calculate the theoretical yield of carbon dioxide in the plastic
3. what is the actual yield in this experiment.
DrBobb222
Answers
Answered by
DrBob222
I worked one like this yesterday. Only the numbers have changed. The process is the same. Try it. I'll help you through if you explain in detail what you don't understand.
Answered by
Zaza
DrBobb222
To determine which reactant is the limiting reactant
if i convert all to mols
like mols of NaHCO3 = 83.99= 84
then 2.00/84 = 0.0238
mols of H3C6H5O7 = 192.123= 192.1
then 0.76/192.1 = 0.0039
CO2 = 44
0.07/44 =0.0016
then CO2 is limiting reactant
is this correct DrBobb222
To determine which reactant is the limiting reactant
if i convert all to mols
like mols of NaHCO3 = 83.99= 84
then 2.00/84 = 0.0238
mols of H3C6H5O7 = 192.123= 192.1
then 0.76/192.1 = 0.0039
CO2 = 44
0.07/44 =0.0016
then CO2 is limiting reactant
is this correct DrBobb222