Asked by Kiana
A constant force acts on a 5.0 kg object and reduces its velocity from 7.0 m/s to 3.0 m/s in a time of 3.0 s. Find the force.
Answers
Answered by
Henry
V = Vo + a*t.
3 = 7 + a*3, a = - 1.333 m/s^2.
F = M*a = 5 * (-1.33) = -6.67 N.
The negative sign means that the force opposes the movement of the object.
3 = 7 + a*3, a = - 1.333 m/s^2.
F = M*a = 5 * (-1.33) = -6.67 N.
The negative sign means that the force opposes the movement of the object.
Answered by
Anonymous
A constant force acts on a 50 kg object and increases its velocity from 4 m/s to 8 m/s in a time of 4 seconds. Find the Force.