Asked by SAM
Rick has 1200 feet of fence that he wants to use to enclose a rectangular garden. Find the maximum area the garden can have.
Answers
Answered by
Damon
I suspect a square
A = L w
L + w = constant = k
L = k - w
so
A = (k-w)w = k w - w^2
dA/dw = k - 2w
= 0 for max or min
so
w = k/2
or w = k = k/2 sure enough a square
so
1200/4 = 300 = L = w
A = 90,000
A = L w
L + w = constant = k
L = k - w
so
A = (k-w)w = k w - w^2
dA/dw = k - 2w
= 0 for max or min
so
w = k/2
or w = k = k/2 sure enough a square
so
1200/4 = 300 = L = w
A = 90,000
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