Asked by Grant

You have 4L feet of fence to make a rectangular vegetable garden alongside the wall of your house, where L is a positive constant. The wall of the house bounds one side of the vegetable garden. What is the largest possible area for the vegetable garden?
Answered by bobpursley
Perimater=4L=2width+1length
or length=4L-2w

area=width(4L-2W)

darea/dw=(4L-2w) + w(-2)=0
width=L
length=2L

check my thinking
Answered by Steve
looks correct. The fence is divided equally among lengths and widths.
Answered by Nia
yes 2L^2 is correct
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