Tan A = 5(Q3), A = 78.7o. S. of W. = 180+78.7 = 258.7o CCW.
Sin B = 2/3(Q2), B = 41.8o N. of W. = 180-41.8 = 138.2o CCW.
A-B = 258.7 - 138.2 = 120.5o, Q2.
Given Tan(A) = 5 in Quadrant III and Sin(B) = ⅔ in Quadrant II, what is the Quadrant of A-B?
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