Asked by Sade
Given Tan(A) = 5 in Quadrant III and Sin(B) = ⅔ in Quadrant II, find Sin(A-B).
Answers
Answered by
Steve
Draw your triangles and quickly see that
sinA = -5/√26
cosA = -1/√26
sinB = 2/3
cosB = -√5/3
now just use your sum-of-angles formula for sin(A-B)
sinA = -5/√26
cosA = -1/√26
sinB = 2/3
cosB = -√5/3
now just use your sum-of-angles formula for sin(A-B)
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