the reaction equation is written in MOLES
2 moles NO plus 1 mole O2 yields
... 2 moles NO2
so 5 moles of O2 uses 10 moles of NO
find the molar (formula) weight of NO, and multiply by 10
2NO(g) + O2 (g) --> 2NO2
How many grams of NO are required to react fully with 5.00 mol of O2?
I do not understand any of this please help
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