Asked by Jonas
write the expression as the logarithm of a single quantity
3[ln x-2 ln(x^2+1)]+2 ln 5
3[ln x-2 ln(x^2+1)]+2 ln 5
Answers
Answered by
sam
3logx-6log(x^2+1)+log25
logx^3-log(x^2+1)+log25
logx^3+log25-log(x^2+1)^6
log(x^3*25/(x^2+1)^6))
logx^3-log(x^2+1)+log25
logx^3+log25-log(x^2+1)^6
log(x^3*25/(x^2+1)^6))
Answered by
Jonas
wait, may I ask you what happened to ln?
Answered by
sam
it is the same thing bro log and ln
Answered by
Damon
ln is log base e
3[ln x-2 ln(x^2+1)]+2 ln 5
ln a - ln b = ln (a/b)
n ln x = ln x^n
so
3 ln [ x/(x^2+1)^2] + ln 25
ln 25[ x/(x^2+1)^2]^3
so agree with Sam
3[ln x-2 ln(x^2+1)]+2 ln 5
ln a - ln b = ln (a/b)
n ln x = ln x^n
so
3 ln [ x/(x^2+1)^2] + ln 25
ln 25[ x/(x^2+1)^2]^3
so agree with Sam
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.