You're right. It isn't correct.
Look at the reactants. H2CO3 is an acid. Sr(OH)2 is a base. The general reaction for an acid and a base produces a salt plus water.
H2CO3 + Sr(OH)2 ==> H2O + SrCO3
Can you add the (aq), (l), (s) to the materials? It isn't balanced. Can you balance it and can you write the net ionic equation now that I've written the molecular equation.
Complete and balance each of the following molecular equations, including phase labels, if a reaction occurs. Then write the net ionic equation. If no reaction occurs, write NR after the arrow.
H2CO3(aq)+Sr(OH)2(aq) ->
this is what I put but I think its wrong
H2CO3(aq)+Sr(OH)2(aq) -> SrO(aq)+CO2(g)+H2O(l)
H2CO3(aq)+2OH^-(aq) -> O^-2(aq)+CO2(g)+H20(l)
2 answers
Yes, thank you. I was trying to do the equation like it was a carbonate that produced carbon dioxide, not as an acid.
4 answers