Asked by Zaza

Sample of 10.7g of O2 reacts completely with CO to form CO2
3a) How many grams of CO2 will be formed. So 10.7g (1mol/32g) (2molCO2/2molCO2)(22.01gCO2/1molCO2) = 14.7g. Please is this right
3b) is the mass of CO2 ypu determined in the equation (3a) the minimum or the maximum amout of CO2 produced in this question.
3c) How many grams of CO is required.
10.7g(1mol/32g)(2molCO/2molCO2)(28.01gCO/1molCO) = 8.8g
Please is due is this correct
Answered by Zaza
i need help Drbob222
Answered by DrBob222
3a isn't correct. I didn't chck the others. It should be
10.7 x(1 mol O2/32g O2) x (2 mols CO2/1 mol O2) x (44 g CO2/mol CO2) = about 29 or so g CO2.
Check your factors. The units don't cancel as they should.
Answered by Zaza
thank you can you check 3c, found my mistake on 3a
3c please is due now @DrBob222
Answered by DrBob222
Sorry to be so long but I had to leave home. The set up for 3c looks ok but I don't get that answer. Check your arithmetic. I get 9+ for an answer.
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