Asked by Wendy
Thank you - (Enter your answers using interval notation. If an answer does not exist, enter DNE.)
y = 4x + [5/sin x], (−π, π)
concave upward (x,y)-
concave downward (x,y)-
y = 4x + [5/sin x], (−π, π)
concave upward (x,y)-
concave downward (x,y)-
Answers
Answered by
Steve
y = 4x + [5/sin x]
= 4x + 5cscx
y' = 4 - 5 cscx cotx
y" = 5/2 csc^3(x) (cos(2x)+3)
cos(2x)+3 is always positive.
on (0,π) csc^3 > 0, so, y is concave up.
similarly, y is concave down on (-π,0)
= 4x + 5cscx
y' = 4 - 5 cscx cotx
y" = 5/2 csc^3(x) (cos(2x)+3)
cos(2x)+3 is always positive.
on (0,π) csc^3 > 0, so, y is concave up.
similarly, y is concave down on (-π,0)
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