Asked by Tyler
I'm trying to enter this so it shows up to what I need, but I need to know how to solve for the missing Letters:
ABCD
X 4
----
DCBA
It reads ABCD times 4 and the 4 is under the D.
ABCD
X 4
----
DCBA
It reads ABCD times 4 and the 4 is under the D.
Answers
Answered by
mike
i thank u have to rearange them
Answered by
tchrwill
ABCD
x 4
DCBA
What does each letter stand for?
1--A must be 1 or 2
2--If A = 1, 4D = 1 cannot be so A = 2.
2BCD
.....x4
DCB2
3--D can be 3 or 8 to give an A = 2
4--If D = 3, 4A cannot be 3 so D = 8.
2BC8
.....x4
8CB2
5--C can be 1, 3, 5, 6, 7, or 9.
6--4C + 3 = 10 + B
....................C....1....3....5....6....7....9
....................B....7....5....3....7....1....9
....................R....0....1....2....2....3....3 R = remainder
4B + R = C....8....1....4....0....7....9
..........................X....X....X....X....Y....X
7--Only C = 7 results in the two C's being equal. (B = 9 from C = 9 would make 4B greater than 10 giving the answer 5 digits.)
8--Therefore, C = 7 and B = 1 for
2178
...x4
8712
x 4
DCBA
What does each letter stand for?
1--A must be 1 or 2
2--If A = 1, 4D = 1 cannot be so A = 2.
2BCD
.....x4
DCB2
3--D can be 3 or 8 to give an A = 2
4--If D = 3, 4A cannot be 3 so D = 8.
2BC8
.....x4
8CB2
5--C can be 1, 3, 5, 6, 7, or 9.
6--4C + 3 = 10 + B
....................C....1....3....5....6....7....9
....................B....7....5....3....7....1....9
....................R....0....1....2....2....3....3 R = remainder
4B + R = C....8....1....4....0....7....9
..........................X....X....X....X....Y....X
7--Only C = 7 results in the two C's being equal. (B = 9 from C = 9 would make 4B greater than 10 giving the answer 5 digits.)
8--Therefore, C = 7 and B = 1 for
2178
...x4
8712
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