at h/4
total mechanical energy
= m g(h/4)+(1/2)m (18)^2
at h
total mechanical energy
= m g h + 0
so
gh = gh/4 + 9*18
for part b
(1/2)m v^2 = m g h
Q23. Object is thrown vertically upwards and has a speed of 18 m/s when it reaches one-fourth of its maximum height h above its launch point. Label the relevant points and answer the following;
a) Determine the maximum height h.
b) What is the initial speed of throwing the object?
1 answer