consider energy:
beginning energy=final energy
1/2 m v1^2=m*3.71*y1
on saturn
1/2 m (1.39v1)^2=m*.264*y2
divide equation 2 by equation 1
1/1.39^2=.264/3.71 * y2/y1
y2=3.71/(.264*1.39^2) * y1
check my math
A 2.83-kg object is thrown vertically upward from the surface of Mars, where the acceleration due to gravity is g1 = 3.71 m/s2. The initial velocity is v1, and the object reaches a maximum height of y1. What is the maximum height, y2, if the object is thrown with a speed of v2 = 1.39v1 from the surface of Saturn\'s moon Rhea? The acceleration due to gravity on Rhea is g2 = 0.264 m/s2. Give your answer as a multiple of y1.
y2=_______* y1
1 answer