Asked by Mary
A coaxial cable 10 feet long is cut into two pieces such that the length of one piece is two-thirds of the length of the other piece. Find the length of the shorter piece of cable.
Answers
Answered by
Ms. Sue
x + (2/3)x = 10
(5/3)x = 10
x = 10 / (5/3)
x = 10 * (3/5)
x = 30/5 = 6
The longer piece is 6 feet long.
Shorter piece = (2/3) * 6
(5/3)x = 10
x = 10 / (5/3)
x = 10 * (3/5)
x = 30/5 = 6
The longer piece is 6 feet long.
Shorter piece = (2/3) * 6
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