Asked by Michelle
A deer runs into the road 1.24 km in front of a car. The driver, traveling at 70.5 km/hr, sees the deer and slams on the brakes which decelerates the car at a rate of 3.2 x 10-1 m/s2. Will the driver hit the deer?
Answers
Answered by
Henry
Vo = 70.5km/h = 70,500m/3600s = 19.6 m/s.
V^2 = Vo^2 + 2a*d.
0 = 19.6^2 - 2*0.32*d, d = ?.
1.24 km = 1240 m.
The stopping distance(d) will be less than 1240 m and the driver stops before hitting the deer.
V^2 = Vo^2 + 2a*d.
0 = 19.6^2 - 2*0.32*d, d = ?.
1.24 km = 1240 m.
The stopping distance(d) will be less than 1240 m and the driver stops before hitting the deer.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.