Question

the population of deer in a certain area of cabarrus county grows proportional to itself. the population of deer in 2000 was found to be 45, and by 2008 the population had grown to 65. Find the growth constant k(rounded to 6 decimal places), and the expected deer population in 2015. (Round to 2 decimal places)

Just need to know the formula and what to plug in where.

Answer 1

You know the growth function will look like

g(t) = a*e^(kt)
So, just plug in your numbers:

g(0) = a = 45
g(8) = 45e^(8k) = 65, so
k = ln(65/45)/8 = 0.046

Now just figure g(15)

Answer 2

wow, I actually did it right, I got .045 for k, and p(t) = 89.67.

I can't believe I actually did this problem correctly, I hope.(crosses fingers)

Answer 3

I meant .046 not .045

Answer 4

I got 89.67 by using 45e^(ln(65/45)/8*15)