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Asked by samuel

the transverse of the conic:3x^2-y^2+2y-1=0 is ???
9 years ago

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Answered by Steve
in standard form, your hyperbola is

3x^2-y^2+2y-1=0
3x^2 - (y-1)^2 = 0
x^2 - (y-1)^2/3 = 0

Your hyperbola is just two intersecting lines, so its transverse is zero! I suspect a typo.
9 years ago
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the transverse of the conic:3x^2-y^2+2y-1=0 is ???

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