Village B is 7km due south of village A and village C is 9km due south of B. Village D is 8km from A and is due east of B. Find DB and DC.

This is a right triangle

(BD)^2 = 7^2+8^2

(DC)^2 = 16^2 +8^2

Can you finish from here??

The diagram please

NO

PLS HELP ME WITH THE COMPLETE SOLUTION

I seem not to under stand, but I will like to have a class with you.Thanks.

Please help us complete it

To find the distances DB and DC, we can use the concept of vector addition. Here are the steps to find the distances:

1. Draw a diagram: Start by drawing a diagram representing the given locations A, B, C, and D. For convenience, put A at the origin (0,0) on a coordinate system.

D
|
|
B--A--C

2. Determine the coordinates: Based on the information given, we can determine the coordinates of each village:
- A: (0,0)
- B: (0, -7) (since B is 7km due south of A)
- C: (0, -7 - 9) = (0, -16) (since C is 9km due south of B)
- D: (8, 0) (since D is due east of B)

3. Find the distances DB and DC:
- DB: To find the distance between D and B, we can use the distance formula:
DB = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Plugging in the coordinates for D (8,0) and B (0, -7):
DB = sqrt((8 - 0)^2 + (0 - (-7))^2)
= sqrt(64 + 49)
= sqrt(113)
≈ 10.63 km

- DC: Similarly, to find the distance between D and C:
DC = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Plugging in the coordinates for D (8,0) and C (0, -16):
DC = sqrt((8 - 0)^2 + (0 - (-16))^2)
= sqrt(64 + 256)
= sqrt(320)
≈ 17.89 km

So, DB is approximately 10.63 km and DC is approximately 17.89 km.