Question

The question is: is (root(x2+2))/x=f(x) even or odd?


I got that it was odd because f(-x)=-f(x) but on the graph it does not look like it is symmetric to the origin


what did i do wrong?

Answer 1

sqrt (x^2+2)
----------
x

The top will be the same for x positive or negative.
However the bottom will change sign but have the same magnitude
Therefore
Odd

Answer 2

check
If x = +5 then
sqrt (27)
---------
5
If x = -5 then
sqrt (27)
-------------
-5

Answer 3

But if you graph it. the graph is not symmetric to the origin. odd functions are always symm to the origin

Answer 4

Gee, it is for me, try -2 and +2
sqrt 6
---------
-2
and
sqrt 6
--------
+2
it is anti-symmetric as It should be