50 (5 + d) + 25 d = 200 (5 - d)
250 + 75 d = 1000 - 200 d
275 d = 750
A 10-ft,25lb seesaw is balanced by a little girl with a weight of 50lbs and her father with a weight of 200lbs at opposite ends. How far from the seesaw's center of mass must the fulcrum be placed?
1 answer