T = Ts + (To-Ts)e^-(kt)
Ts = T surrounding = 10
To = initial T = 160
60 = 10 +(150)e^-(5k)
e^-(5k) = .333333
-5k = -1.1
k = .22
so
20 = 10 + 150 e^-.22t
e^-.22 t = .0666666
.22t = 2.71
t = 12.3 min
12.3 - 5 = 7.3 min more
A container of hot liquid is placed in a freezer that is kept at a constant temperature of 10°F. The initial temperature of the liquid is 160°F. After 5 minutes, the liquid's temperature is 60°F. How much longer will it take for its temperature to decrease to 20°F? (Round your answer to two decimal places.)
I know you have to use Newton's Law of Cooling, but I keep ending up with the wrong answer
2 answers
Thank you so much I realized I was missing the -5 at the end
1 answer