Question

The energy released by a heater which draws a current of 5A at 220V for 1min.

E ~ V × I× t( hrs)÷1000
220×5×0.0167÷60000
Is equal to 0.00030 Kwh

Answer 1

E(kwh)=220*5*1/60 * 1/1000
I don't understand your .0167 number.