Asked by lhamo
                The energy released by a heater which draws a current of 5A at 220V for 1min.
E ~ V × I× t( hrs)÷1000
220×5×0.0167÷60000
Is equal to 0.00030 Kwh
            
        E ~ V × I× t( hrs)÷1000
220×5×0.0167÷60000
Is equal to 0.00030 Kwh
Answers
                    Answered by
            bobpursley
            
    E(kwh)=220*5*1/60 * 1/1000
I don't understand your .0167 number.
    
I don't understand your .0167 number.
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.