Asked by lhamo

The energy released by a heater which draws a current of 5A at 220V for 1min.

E ~ V × I× t( hrs)÷1000
220×5×0.0167÷60000
Is equal to 0.00030 Kwh
Answered by bobpursley
E(kwh)=220*5*1/60 * 1/1000
I don't understand your .0167 number.
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