50 g of U-235 is 50/235 = 0.2128 moles.
Multiply that by Avogadro's number for the number of atoms.
200 MeV = 200*10^6 eV*1.602*10^-19 J/eV
= 3.2*10^-11 J
E = 0.2128 moles*6.02^10^23 atoms/mole*3.2*10^-11 J/atom =
Multiply that by Avogadro's number for the number of atoms.
200 MeV = 200*10^6 eV*1.602*10^-19 J/eV
= 3.2*10^-11 J
E = 0.2128 moles*6.02^10^23 atoms/mole*3.2*10^-11 J/atom =
Step 1: Find the molar mass of Uranium-235.
The molar mass of Uranium-235 (U-235) can be found in the periodic table or online sources. It is approximately 235 g/mol.
Step 2: Determine the number of moles of Uranium-235.
The number of moles can be calculated using the formula:
Number of moles = Mass / Molar mass
Number of moles of Uranium-235 = 50 g / 235 g/mol
Step 3: Calculate the Avogadro's number.
Avogadro's number (NA) is a constant that represents the number of particles (atoms or molecules) in one mole of a substance. It is approximately 6.022 x 10^23 particles/mol.
Step 4: Calculate the number of Uranium-235 atoms.
Number of atoms = Number of moles × Avogadro's number
Number of Uranium-235 atoms = Number of moles × NA
Step 5: Calculate the number of fissions.
Each fission of a Uranium-235 nucleus releases energy, so the number of fissions is equal to the number of Uranium-235 atoms.
Number of fissions = Number of Uranium-235 atoms
Step 6: Calculate the total energy released.
The total energy released can be calculated by multiplying the number of fissions by the energy released per fission.
Total energy released = Number of fissions × Energy released per fission
Now let's substitute the given values into the equations and find the answers:
Number of moles of Uranium-235 = 50 g / 235 g/mol
Number of Uranium-235 atoms = Number of moles × NA
Number of fissions = Number of Uranium-235 atoms
Total energy released = Number of fissions × Energy released per fission
I will calculate these values for you:
Number of moles of Uranium-235 = 0.2128 mol
Number of Uranium-235 atoms ≈ 1.28 × 10^23 atoms
Number of fissions ≈ 1.28 × 10^23 atoms
Total energy released ≈ (1.28 × 10^23 atoms) × (200 MeV)