Asked by Annie
Please help I'm stuck on this problem for the past hour.
Define f(x)= { Ln lx-1l }/x
A) show that f(c) is continuous at x=2
B)Where on the interval [-2,2] is f discontinuous? Show the work that leads to your conclusion.
C) classify the discontinuities in part b) as removable or no removable.
Like, I know that IVT is involved, but how is it used to solve this?
Define f(x)= { Ln lx-1l }/x
A) show that f(c) is continuous at x=2
B)Where on the interval [-2,2] is f discontinuous? Show the work that leads to your conclusion.
C) classify the discontinuities in part b) as removable or no removable.
Like, I know that IVT is involved, but how is it used to solve this?
Answers
Answered by
bobpursley
well, when x=0 the function is undefined. When x=1, it is undefined because of the ln function.
Answered by
Steve
f(0) is undefined, but the limit is -1 at x=0.
So, there's a removable discontinuity at x=0.
Naturally, at x=1, f is undefined; there's an asymptote there.
Take a look at the graph for further justification of your analysis:
http://www.wolframalpha.com/input/?i=ln%7Cx-1%7C%2Fx
So, there's a removable discontinuity at x=0.
Naturally, at x=1, f is undefined; there's an asymptote there.
Take a look at the graph for further justification of your analysis:
http://www.wolframalpha.com/input/?i=ln%7Cx-1%7C%2Fx
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.