Asked by marjean
A step-up transformer used in a car has a potential difference of 10 V across the primary coil with 12 turns. What is the current in the secondary coil of resistance 2.5 Ω if the number of turns in the secondary coil is 54 turns?
Answers
Answered by
Morgoth
Using the equation, we can find the emf across the secondary coil.
Ns/Np = Vs/Vp
Vs = Vp(Ns/Np)
Vs = 10(54/12)
Vs = 45V
I = 45/2.5
I = 18 A
Ns/Np = Vs/Vp
Vs = Vp(Ns/Np)
Vs = 10(54/12)
Vs = 45V
I = 45/2.5
I = 18 A
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