Ask a New Question
Menu

A video game console operates potential difference of 12.00 V as shown in fig. The potential difference supplied by the power receptacle is 120 V AC. A transformer is used to convert one voltage to the other. If the secondary coil of the transformer (the 12.00 V side) has 1200 loops, how many loops does the primary coil have?

User Icon for Arora Arora answered
6 years ago

In a transformer, the ratio of the voltages on either side is directly proportional to the ratio of the number of loops.

=> V1/N1 = V2/N2

In this case, V1 = 12V, N1 = 1200, V2 = 120V

=> 12/1200 = 120/N2
=> N2 = 12,000

User Icon for bobpursley bobpursley answered
6 years ago

Within a magnetic core magnetic flux occurs. The flux is dependent on the primary current, and the primary turns

Ip*Np. This same flux flows in the core of the secondary, Is*Ns
so IpNp=Is*Ns
now on voltage, in accordance with Lenz's law, this flux causes in each turn, an induced voltage. so the total induced voltage is k*voltage/turn*turns *flux
Vs=kNs*flux
or Vs/Ns=k*flux. But on the primary, the same constant k isoccuring in generating the flux, so
Vs/Ns=Vp/Np
or
Vp/Vs=Np/Ns
120/12=1200/Ns
or Ns=12,000 turns.

User Icon for Explain Bot Explain Bot answered
11 months ago

To determine the number of loops in the primary coil, we can use the formula for the turns ratio of a transformer:

Turns ratio = number of turns in the secondary coil / number of turns in the primary coil

In this case, the turns ratio is given by:

Turns ratio = 12.00 V / 120 V = 0.1

Since the turns ratio is equal to the ratio of the number of turns, we have:

0.1 = number of turns in the secondary coil / number of turns in the primary coil

Now, let's solve for the number of turns in the primary coil:

number of turns in the primary coil = number of turns in the secondary coil / 0.1

number of turns in the primary coil = 1200 / 0.1

number of turns in the primary coil = 12,000

Therefore, the primary coil of the transformer has 12,000 loops.