Asked by Nelson
The width of a rectangle is 8 less than twice its length. If the area of the rectangle is 172 cm^2, what is the length of the diagonal?
Answers
Answered by
PsyDAG
W = 2L - 8
W * L = 172
Substitute 2L-8 for W in the second equation and solve for L. Insert that value into the first equation to solve for W. Check by putting both values into the second equation.
Then use Pythagorean theorem.
W^2 + L^2 = diagonal^2
W * L = 172
Substitute 2L-8 for W in the second equation and solve for L. Insert that value into the first equation to solve for W. Check by putting both values into the second equation.
Then use Pythagorean theorem.
W^2 + L^2 = diagonal^2