Zn + 2HCl ==> H2 + ZnCl2
mols Zn = grams Zn/atomic mass Zn = ?
Using the coefficients in the balanced equation, convert mols Zn to mols HCl. That will be mols Zn x 2 = mols HCl.
Then M = mols/L. You know M of HCl, mols HCl, solve for L HCl and convert to mL
How many milliliters of a 0.48 M HCl solution
are needed to react completely with 7.4 g of
zinc to form zinc(II) chloride?
Answer in units of mL.
1 answer
1 answer